1865 Iowa gubernatorial election

1865 Iowa gubernatorial election
October 10, 1865
 
Nominee William M. Stone Thomas H. Benton
Party Republican Democratic
Popular vote 70,461 54,090
Percentage 56.41% 43.31%
County results
Stone:      50–60%      60–70%      70–80%      80–90%      90–100%
Benton:      50–60%      60–70%      70–80%      80–90%
No Data/Votes:      
Governor before election

William M. Stone
Republican

Elected Governor

William M. Stone
Republican

The 1865 Iowa gubernatorial election was held on October 10, 1865, in order to elect the governor of Iowa. Incumbent Republican governor William M. Stone was re-elected against Democratic nominee Thomas H. Benton.[1]

General election

On election day, October 10, 1865, incumbent Republican governor William M. Stone won re-election by a margin of 16,371 votes against his opponent Democratic nominee Thomas H. Benton, thereby holding Republican control over the office of governor. Stone was sworn in for his second term on January 16, 1866.[2]

Results

Iowa gubernatorial election, 1865[3]
Party Candidate Votes %
Republican William M. Stone 70,461 56.41
Democratic Thomas H. Benton 54,090 43.31
Scattering 353 0.28
Total votes 124,904 100.00
Republican hold

References

  1. ^ "William Milo Stone". National Governors Association. Retrieved 2023-11-28.
  2. ^ "IA Governor". ourcampaigns.com. July 25, 2005. Retrieved 2023-11-28.
  3. ^ Iowa General Assembly. Journal of the House of Representatives. 1866 sess., 3, accessed November 28, 2023
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