1854 Iowa gubernatorial election

1854 Iowa gubernatorial election
August 7, 1854
 
Nominee James W. Grimes Curtis Bates
Party Whig Democratic
Popular vote 23,312 21,192
Percentage 52.38% 47.62%
County results
Grimes:      50–60%      60–70%      70–80%      >90%
Bates:      50–60%      60–70%      70–80%      80–90%      >90%
No Data/Votes:      
Governor before election

Stephen P. Hempstead
Democratic

Elected Governor

James W. Grimes
Whig

The 1854 Iowa gubernatorial election was held on August 7, 1854, in order to elect the Governor of Iowa. Whig nominee James W. Grimes defeated Democratic nominee Curtis Bates.[1]

General election

On election day, August 7, 1854, Whig nominee James W. Grimes won the election by a margin of 2,120 votes against his opponent Democratic nominee Curtis Bates, thereby gaining Whig control over the office of Governor. Grimes was sworn in as the 3rd Governor of Iowa on December 9, 1854.[2]

Results

Iowa gubernatorial election, 1854[3]
Party Candidate Votes %
Whig James W. Grimes 23,312 52.38
Democratic Curtis Bates 21,192 47.62
Total votes 44,504 100.00
Whig gain from Democratic

References

  1. ^ "James Wilson Grimes". National Governors Association. Retrieved 2023-11-27.
  2. ^ "IA - Governor". ourcampaigns.com. March 4, 2005. Retrieved 2023-11-27.
  3. ^ Iowa General Assembly. Journal of the House of Representatives. 1854 sess., 42, accessed November 27, 2023
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