1826 Maryland gubernatorial election

1826 Maryland gubernatorial election
January 2, 1826
 
Nominee Joseph Kent William Tyler
Party Democratic-Republican
Popular vote 59 30
Percentage 65.56% 33.33
Governor before election

Samuel Stevens Jr.
Democratic-Republican

Elected Governor

Joseph Kent
Democratic-Republican

The 1826 Maryland gubernatorial election was held on January 2, 1826, in order to elect the Governor of Maryland. Democratic-Republican nominee and incumbent member of the U.S. House of Representatives from Maryland's 2nd district Joseph Kent was elected by the Maryland General Assembly against candidates William Tyler and Thomas H. Carroll.[1]

General election

On election day, January 2, 1826, Democratic-Republican nominee Joseph Kent was elected by the Maryland General Assembly, thereby retaining Democratic-Republican control over the office of governor. Kent was sworn in as the 19th Governor of Maryland on January 9, 1826.[2]

Results

Maryland gubernatorial election, 1826
Party Candidate Votes %
Democratic-Republican Joseph Kent 59 65.56
William Tyler 30 33.33
Thomas H. Carroll 1 1.11
Total votes 90 100.00
Democratic-Republican hold

References

  1. ^ "Joseph Kent". National Governors Association. Retrieved 2024-04-27.
  2. ^ "MD Governor". ourcampaigns.com. March 28, 2005. Retrieved 2024-04-27.


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