1788–89 United States presidential election in Connecticut

1788–1789 United States presidential election in Connecticut

January 7, 1789
 
Nominee George Washington John Adams Samuel Huntington
Party Independent Federalist Federalist
Home state Virginia Massachusetts Connecticut
Electoral vote 7 5 2
Percentage 100.00%

President before election

Office established

Elected President

George Washington
Independent

A presidential election was held in Connecticut on January 7, 1789, as part of the 1789 United States presidential election. The state legislature chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.[1]

Connecticut, which became the 5th state on January 9, 1788, unanimously cast its seven electoral votes for George Washington during its first presidential election.

Results

1788-89 United States presidential election in Connecticut[2]
Party Candidate Electoral Vote %
Independent George Washington 7 100.00%
Total votes 7 100.00%

Results by elector

1788-89 United States presidential election in Connecticut[2]
Party Candidate Electoral Vote[a]
Federalist Erastus Wolcott John Adams/Samuel Huntington
Federalist Jedediah Huntington John Adams/Samuel Huntington
Federalist Matthew Griswold John Adams/Samuel Huntington
Federalist Oliver Wolcott Sr. John Adams/Samuel Huntington
Federalist Richard Law John Adams/Samuel Huntington
Federalist Samuel Huntington John Adams/Samuel Huntington
Federalist Thaddeus Burr John Adams/Samuel Huntington

See also

Notes

  1. ^ It is not known which two electors voted for Samuel Huntington.[2]

References

  1. ^ "The Electoral Count for the Presidential Election of 1789". The Papers of George Washington. Archived from the original on September 14, 2013. Retrieved May 4, 2005.
  2. ^ a b c Jensen & Becker 1976, p. xxvii.

Works cited