1788–89 United States presidential election in Georgia|
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A presidential election was held on January 7, 1789, in Georgia, as part of the 1788–89 United States presidential election. The state legislature chose 5 representatives, or electors to the Electoral College, who voted for President and Vice President.
George Handley, John King, George Walton, Henry Osborne, and John Milton served as electors. The electors cast five votes for George Washington, two for Milton, one for James Armstrong, one for Edward Telfair, and one for Benjamin Lincoln.
Results
1788-89 United States presidential election in Georgia
| Party
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Candidate
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Electoral Vote
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%
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Independent
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George Washington
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5
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100.00%
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| Total votes
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5
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100.00%
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Results by elector
See also
Notes
- ^ The results of which candidate each elector voted for vice president is not known.
References
Works cited
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U.S. President | |
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U.S. Senate | |
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U.S. House | |
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State legislative | |
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| States |
- Connecticut
- Delaware
- Maryland
- Massachusetts
- New Hampshire
- New Jersey
- Pennsylvania
- South Carolina
- Virginia
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