2026 Australian Open – Wheelchair women's singles

Wheelchair women's singles
2026 Australian Open
Champion Li Xiaohui
Runner-up Diede de Groot
Score6–1, 6–2
Draw16
Seeds4

Li Xiaohui defeated Diede de Groot in the final, 6–1, 6–2 to win the women's singles wheelchair tennis title at the 2026 Australian Open.[1] It was her first major singles title.[2]

Yui Kamiji was the defending champion,[3] but lost to Li in the semifinals.

Seeds

  1. Yui Kamiji (semifinals)
  2. Aniek van Koot (quarterfinals)
  3. Li Xiaohui (champion)
  4. Wang Ziying (semifinals)

Draw

Key

Draw

First round Quarterfinals Semifinals Final
1 Yui Kamiji 6 6
Jiske Griffioen 2 2 1 Y Kamiji 6 6
Zhu Zhenzhen 1 77 4 L de Greef 1 2
Lizzy de Greef 6 63 6 1 Y Kamiji 6 2 68
3 Li Xiaohui 6 3 6 3 X Li 3 6 710
Ksénia Chasteau 2 6 1 3 X Li 6 6
Q Momoko Ohtani 6 7 Q M Ohtani 3 2
Manami Tanaka 3 5 3 X Li 6 6
Angélica Bernal 5 4 D de Groot 1 2
Kgothatso Montjane 7 6 K Montjane 4 2
WC Guo Luoyao 3 4 4 Z Wang 6 6
4 Wang Ziying 6 6 4 Z Wang 4 6 69
Diede de Groot 6 6 D de Groot 6 3 711
WC Jinte Bos 0 3 D de Groot 6 6
Q Maayan Zikri 0 2 2 A van Koot 2 2
2 Aniek van Koot 6 6

Qualifying

Seeds

  1. Saki Takamuro (qualifying competition)
  2. Lucy Shuker (qualifying competition)

Qualifiers

  1. Momoko Ohtani
  2. Maayan Zikri

Qualifying draw

Qualifying competition
1 Saki Takamuro 5 3
Momoko Ohtani 7 6
Qualifying competition
Maayan Zikri 2 6 7
2 Lucy Shuker 6 3 5

References

  1. ^ "Li Xiaohui wins women's wheelchair singles final at Australian Open tennis tournament". Xinhua. Retrieved 31 January 2026.
  2. ^ "Li breaks through for maiden Grand Slam title win". Australian Open. Retrieved 31 January 2026.
  3. ^ "Kamiji secures ninth grand slam singles victory". ausopen.com. Retrieved 25 January 2025.