1998 Budapest Lotto Open – Doubles

Doubles
1998 Budapest Lotto Open
Champions Virginia Ruano Pascual
Paola Suárez
Runners-up Cătălina Cristea
Laura Montalvo
Score4–6, 6–1, 6–1

Amanda Coetzer and Alexandra Fusai were the defending champions but did not compete that year.[1]

Virginia Ruano Pascual and Paola Suárez won in the final 4–6, 6–1, 6–1 against Cătălina Cristea and Laura Montalvo.[2]

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

  1. Virginia Ruano Pascual / Paola Suárez (champions)
  2. Cătălina Cristea / Laura Montalvo (final)
  3. Svetlana Krivencheva / Eva Melicharová (quarterfinals)
  4. Laura Golarsa / Liezel Horn (semifinals)

Draw

Key

First round Quarterfinals Semifinals Final
1 V Ruano Pascual
P Suárez
6 6  
  E Bes
K Marosi
0 1   1 V Ruano Pascual
P Suárez
6 6  
  S Naćuk
P Wartusch
6 1 6   S Naćuk
P Wartusch
1 0  
  J Halard-Decugis
J Husárová
3 6 4 1 V Ruano Pascual
P Suárez
6 6  
4 L Golarsa
L Horn
6 4 6 4 L Golarsa
L Horn
3 3  
  P Gáspár
A-G Sidot
4 6 3 4 L Golarsa
L Horn
6 6  
WC Z Gubacsi
R Kuti-Kis
6 6   WC Z Gubacsi
R Kuti-Kis
4 2  
Q E Doman
A Piski
4 3   1 Virginia Ruano Pascual
Paola Suárez
4 6 6
  A Dechaume-Balleret
B Rittner
      2 Cătălina Cristea
Laura Montalvo
6 1 1
  N Dechy
L Ghirardi
w/o       N Dechy
L Ghirardi
6 6  
  E Kulikovskaya
K Studeníková
2 1   3 S Krivencheva
E Melicharová
4 2  
3 S Krivencheva
E Melicharová
6 6     N Dechy
L Ghirardi
2 6 1
  S Cecchini
W Probst
4 1   2 C Cristea
L Montalvo
6 2 6
  S Farina
S Testud
6 6     S Farina
S Testud
3 3  
  V Csurgó
T Križan
3 5   2 C Cristea
L Montalvo
6 6  
2 C Cristea
L Montalvo
6 7  

References

  1. ^ "1997 Budapest Lotto Open". www.itftennis.com. Retrieved 2026-03-01.
  2. ^ "WTA Budapest Doubles 1998 Draw - Tennis/WTA - Doubles". www.flashscore.com. Retrieved 2026-03-01.