1890 New Hampshire gubernatorial election

1890 New Hampshire gubernatorial election
November 4, 1890
	Tuttle: 40-50% 50–60% 60–70% 70–80% 80–90%; Amsden: 40-50% 50–60% 60–70% 70–80% 80–90% 90-100%; Tie: 40-50% 50%
Governor before election; David H. Goodell; Republican	Elected Governor ; Hiram A. Tuttle; Republican

The 1890 New Hampshire gubernatorial election was held on November 4, 1890. Republican nominee Hiram A. Tuttle defeated Democratic nominee Charles H. Amsden with 49.26% of the vote.

General election

Candidates

Major party candidates

Hiram A. Tuttle, Republican
Charles H. Amsden, Democratic

Other candidates

Josiah M. Fletcher, Prohibition

Results

1890 New Hampshire gubernatorial election^[1]
Party		Candidate	Votes	%
	Republican	Hiram A. Tuttle	42,479	49.26%
	Democratic	Charles H. Amsden	42,386	49.15%
	Prohibition	Josiah M. Fletcher	1,343	1.56%
Majority			93
Turnout
	Republican hold		Swing

References

^ Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved July 16, 2020.

[1] Kalb, Deborah (December 24, 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved July 16, 2020.

[1]