1849 Maine gubernatorial election
September 10, 1849
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County results Hubbard: 40–50% 50–60% 60–70% Hamlin: 40–50% | |||||||||||||||||||||
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| Elections in Maine |
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The 1849 Maine gubernatorial election was held on September 10, 1849, in order to elect the Governor of Maine. Democratic nominee and former member of the Maine Senate John Hubbard defeated Whig nominee and former member of the Maine House of Representatives Elijah Hamlin and Free Soil Party nominee George F. Talbot.[1]
General election
On election day, September 10, 1849, Democratic nominee John Hubbard won the election by a margin of 9,580 votes against his foremost opponent Whig nominee Elijah Hamlin, thereby retaining Democratic control over the office of governor. Hubbard was sworn in as the 22nd governor of Maine on May 8, 1850.[2]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | John Hubbard | 37,636 | 51.01 | |
| Whig | Elijah Hamlin | 28,056 | 38.03 | |
| Free Soil | George F. Talbot | 7,987 | 10.83 | |
| Scattering | 102 | 0.13 | ||
| Total votes | 73,781 | 100.00 | ||
| Democratic hold | ||||
References
- ^ "Gov. John Hubbard". nga.org. Retrieved 2024-04-16.
- ^ "ME Governor". ourcampaigns.com. April 21, 2005. Retrieved 2024-04-16.