1804 United States presidential election in New Jersey
November 2 – December 5, 1804
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| Elections in New Jersey |
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The 1804 United States presidential election in New Jersey took place between November 2 and December 5, 1804, as part of the 1804 United States presidential election. The state chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.
During this election, New Jersey cast eight electoral votes for Democratic Republican incumbent Thomas Jefferson.[1]
Results
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | Thomas Jefferson | 13,119 | 99.86% | |
| Federalist | Charles Cotesworth Pinckney | 19 | 0.14% | |
| Total votes | 13,138 | 100.00% | ||
Results by county
| County | Charles Cotesworth Pinckney
Federalist |
Thomas Jefferson
Democratic-Republican |
Margin | Total
votes[a] | |||
|---|---|---|---|---|---|---|---|
| # | % | # | % | # | % | ||
| Bergen | - | 0.00% | - | 0.00% | - | 0.00% | - |
| Burlington | - | 0.00% | - | 0.00% | - | 0.00% | - |
| Cape May | - | 0.00% | - | 0.00% | - | 0.00% | - |
| Cumberland | 1 | 0.13% | 765 | 99.87% | -764 | -99.74% | 766 |
| Essex | 0 | 0.00% | 2,523 | 100.00% | -2,523 | -100.00% | 2,523 |
| Gloucester | 2 | 0.22% | 906 | 99.78% | -904 | -99.56% | 908 |
| Hunterdon | 0 | 0.00% | 1,342 | 100.00% | -1,342 | -100.00% | 1,342 |
| Middlesex | - | 0.00% | - | 0.00% | - | 0.00% | - |
| Monmouth | 1 | 0.14% | 713 | 99.86% | -712 | -99.72% | 714 |
| Morris | - | 0.00% | - | 0.00% | - | 0.00% | - |
| Salem | 0 | 0.00% | 864 | 100.00% | -864 | -100.00% | 864 |
| Somerset | 4 | 0.71% | 560 | 99.29% | -556 | -98.58% | 564 |
| Sussex | 6 | 0.39% | 1,518 | 99.61% | -1,512 | -99.22% | 1,524 |
| Total | 14 | 0.15% | 9,191 | 99.85% | -9,177 | -99.70% | 9,205 |
See also
Notes
References